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Now that we have
the cylinder picked out,
we can choose a pump.
First, let's decide
whether we want a
positive or non-positive
displacement pump.
That sounds
complicated.
It's really easy
in our case.
We need our pump to
continue putting out max
flow even through the hard
work of splitting a log.
A non-positive pump
would never do that.
It would quit putting
out max flow as soon
as the work got hard.
And no one
likes a quitter!
Now the positive displacement
pump, on the other hand,
pushes flow through the
system at a steady rate...
...even if it meets
high resistance.
Perfect, right?
But the real problem
is: what kind of positive
displacement pump to use.
Do either of you kids know
how to choose the
best positive displacement
pump for our system?
No.
Don't sweat it!
There are a ton of options,
but a simple process of
elimination will allow us
to pick the right one.
First, let's choose whether
we need a fixed or variable
positive displacement pump.

Table of Contents

Fixed Displacement Pump.......... pg.2-4
Variable Displacement Pump.......... pg.5-8

Notes:

Fixed Displacement Pump: Does not have a
control to change its displacement. As long
as it's receiving enough fluid, it always
displaces the same amount. Can only
displace more fluid by spinning faster.


Variable Displacement Pump: Can control its
displacement without having to change how
fast it spins. Best for cases where you
need nuanced speed control.

Fixed or Variable?

For this simple system, we don’t need to change
the speed at which we split logs. We might want to
restrict flow if we want to slow down the log
splitting a bit, but beyond that it's more or less
“put log in, hit go”.

So our system can operate on a steady flow rate
and we don’t ever need to change the pump
displacement. Which of the following types should
we pick?

Alright, we know we need
a fixed displacement pump.
A simple gear pump
should do the trick.
Let's see if we can find
one in our catalogue.
There are so many
of them. How do
we choose?
It depends how fast we want
our cylinder to extend and
retract.
In other words, how
fast do we want to
split these logs?
Faster than
Frank?
I like your
thinking.
We should go for just
the right speed: not so
fast that it'll be unsafe
for the cylinder, but still
fast enough to give us
an edge on Frank.

0.38 CID/rpm
hydraulic gear
pump 3/4" keyed
shaft CW
$142

0.5 CID/rpm
hydraulic gear
pump 3/4" keyed
shaft CW
$146

0.61 CID/rpm
hydraulic gear
pump 3/4" keyed
shaft CW
$150

Notes:

  • Upon covert observation with the help of a stopwatch, we have observed that the cylinder on
    Frank's machine takes 12.1 seconds to fully extend and 8.9 seconds to fully retract. Let's see if we
    can find something a little faster, while still picking the cheapest option.

  • We will choose a pump based on its Cubic Inch Displacement (CID) per rpm (rotations per minute).
    A higher CID = higher cylinder speed.

  • 0.38 CID Pump

    Things We Know:

  • Our cylinder is rated to 3500 psi, has a 3.5" internal diameter (bore), a 20" stroke, and a 1.75" rod diameter.
  • Billy's motor spins at 2000 rpm, and a max hp of 10hp.
  • Our system pressure will be around 2000 psi.
  • 𝛑 = 3.14

  • 1. Pump GPM

    CID x RPM ÷ 231 = GPM

    GPM = gpm

    4.335.28

    2. Find hp

    GPM x Pressure ÷ 1714 = hp

    hp = hp

    5.056.16

    3a. Cylinder Extend Volume

    𝛑 x (Cylinder Bore ÷ 2)2 x Stroke = Extend Volume

    Extend Volume = inches3

    185.46153.98

    3b. Cylinder Extend Speed

    (60 x Extend Volume) ÷ (231 x GPM) = Extend Speed

    Extend Speed = sec.

    **faster than 12.1 seconds = good

    11.549.46

    4a. Cylinder Retract Volume

    Extend Volume — (𝛑 x (Rod Diameter ÷ 2)2 x Stroke) = Retract Volume

    Retract Volume = inches3

    135.75153.98

    4b. Cylinder Retract Speed

    (60 x Retract Volume) ÷ (231 x GPM) = Retract Speed

    Retract Speed = sec.

    **faster than 8.9 seconds = good

    8.657.10

    0.50 CID Pump

    Things We Know:

  • Our cylinder is rated to 3500 psi, has a 3.5" internal diameter (bore), a 20" stroke, and a 1.75" rod diameter.
  • Billy's motor spins at 2000 rpm, and a max hp of 10hp.
  • Our system pressure will be around 2000 psi.
  • 𝛑 = 3.14

  • 1. Pump GPM

    CID x RPM ÷ 231 = GPM

    GPM = gpm

    3.295.28

    2. Find hp

    GPM x Pressure ÷ 1714 = hp

    hp = hp

    3.846.16

    3a. Cylinder Extend Volume

    𝛑 x (Cylinder Bore ÷ 2)2 x Stroke = Extend Volume

    Extend Volume = 192.33 inches3

    3b. Cylinder Extend Speed

    (60 x Extend Volume) ÷ (231 x GPM) = Extend Speed

    Extend Speed = sec.

    **faster than 12.1 seconds = good

    15.189.46

    4a. Cylinder Retract Volume

    Extend Volume — (𝛑 x (Rod Diameter ÷ 2)2 x Stroke) = Retract Volume

    Retract Volume = 144.25 inches3

    4b. Cylinder Retract Speed

    (60 x Retract Volume) ÷ (231 x GPM) = Retract Speed

    Retract Speed = sec.

    **faster than 8.9 seconds = good

    11.37.10

    0.61 CID Pump

    Things We Know:

  • Our cylinder is rated to 3500 psi, has a 3.5" internal diameter (bore), a 20" stroke, and a 1.75" rod diameter.
  • Billy's motor spins at 2000 rpm, and a max hp of 10hp.
  • Our system pressure will be around 2000 psi.
  • 𝛑 = 3.14

  • 1. Pump GPM

    CID x RPM ÷ 231 = GPM

    GPM = gpm

    3.294.33

    2. Find hp

    GPM x Pressure ÷ 1714 = hp

    hp = hp

    3.845.05

    3a. Cylinder Extend Volume

    𝛑 x (Cylinder Bore ÷ 2)2 x Stroke = Extend Volume

    Extend Volume = 192.33 inches3

    3b. Cylinder Extend Speed

    (60 x Extend Volume) ÷ (231 x GPM) = Extend Speed

    Extend Speed = sec.

    **faster than 12.1 seconds = good

    15.1811.54

    4a. Cylinder Retract Volume

    Extend Volume — (𝛑 x (Rod Diameter ÷ 2)2 x Stroke) = Retract Volume

    Retract Volume = 144.25 inches3

    4b. Cylinder Retract Speed

    (60 x Retract Volume) ÷ (231 x GPM) = Retract Speed

    Retract Speed = sec.

    **faster than 8.9 seconds = good

    11.38.65

    0.38 CID/rpm
    hydraulic gear
    pump 3/4" keyed
    shaft CW
    $142

    0.5 CID/rpm
    hydraulic gear
    pump 3/4" keyed
    shaft CW
    $146

    0.61 CID/rpm
    hydraulic gear
    pump 3/4" keyed
    shaft CW
    $150

    Which pump is our best choice?

    Extend Speed = 15.18 sec.

    Retract Speed = 11.39 sec.

    Extend Speed = 11.54 sec.

    Retract Speed = 8.65 sec.

    Extend Speed = 9.46 sec.

    Retract Speed = 7.10 sec.

    Our cylinder's
    gonna be so fast.
    We'll beat Frank
    for sure!
    Let's not get ahead
    of ourselves.
    Yes, our cylinder will
    be faster. But speed
    alone is not enough to
    beat Frank.
    Then what
    is?
    Speed...
    ...and Power!
    This engine of mine
    might be enough to
    power our pump. It's
    certainly powerful
    enough if we're just
    pushing our cylinder
    through open air.
    But that's obviously
    not all we need it to do.
    We need it to
    drive through logs!
    As you know, we picked a positive
    displacement pump, which keeps putting
    out flow...
    ...even through the
    hard work of splitting
    a log.
    But the pump will do us
    no good if our engine's
    not powerful enough to
    keep it running.
    If our engine doesn't have
    enough power to meet the
    system's pressure demands,
    it might just give up and
    quit in the middle of the race!
    If we're gonna beat Frank,
    we have to be confident that
    our engine will continue powering
    our pump through even the
    toughest logs.
    How do we know
    if it's powerful
    enough?
    We can easily find out using
    the stuff we already know
    about our pump, engine, and
    system. Plus a few handy
    formulas.

    Power Calculations

    Things We Know:

    System Stats (from FPA Triangle Calculations): 2000 psi max pressure

    Displacement Pump Stats: 0.5 inch3(CID) displacement pump

    Billy's Engine Stats: 10hp at 2000 rpm (highest engine speed)


    Calculations:

    1. Flow Rate at Highest Engine Speed (gallons per minute)

    (Engine Speed (rpm) x Displacement (inch3)) ÷ 231 = gpm

    This is our flow rate when the engine is running at full speed.

    7.815.6

    2. Can this flow rate be mainatined when chopping logs (system pressure of 2000 psi)?
    Check if we have enough hp to maintain the flow rate at this pressure

    (Pressure (psi) x Flow (gpm)) ÷ 1714 = Horsepower (hp)

    Required hp = hp

    1.18.6

    10hp = good

    Will Billy's 10 hp engine work?

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